Someone deposited 1 99965438+1October1in the bank, with the annual interest rate of 10%. Required calculation: (1) compound interest once a year, and the balance of the deposit account in June 2002 is

Someone deposited 1 99965438+1October1in the bank, with the annual interest rate of 10%. Required calculation: (1) compound interest once a year, and the balance of the deposit account in June 2002 is 65438+ 10/. 1. Compound interest once a year. On June 65438+10/October 65438 +0, 2002, the balance of the deposit account was

1000*( 1+ 10%)^3= 133 1

2. Compound interest once every quarter. What is the balance of the deposit account of 65438+1 October1in June 2002?

1000*( 1+ 10%/4)^ 12= 1344.89

3. If 1999-2006 deposit 65,438+0 at the 250 yuan interest rate of 65,438+00% respectively, the balance at the beginning of 2002 will be compounded once a year.

250*(( 1+ 10%)^3- 1)/ 10%*( 1+ 10%)=9 10.25

Suppose you deposit the same amount in four years. In order to reach the account balance in the first question, how much should you deposit in each period?

Annual initial deposit:1210/(1+10%) 4-1) *10%/(1+/kloc-)

Year end:1210/((1+10%) 4-1) *10% = 260.72.