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y=ax？ +bx+c=a(x+b/2a)？ +c-b？ /(4a) (a≠0)
When a > 0, the opening of the quadratic function image is upward and there is a minimum value.
When x=-b/2a, the minimum value of y =c-b? /(4a)=(4ac-b？ )/(4a)