1. The proband shows that △ABF is congruent to △CED, the h
1. The proband shows that △ABF is congruent to △CED, the hypotenuse of a right triangle and the hypotenuse of a right triangle. What will it be?
Obtain BF=DE
AAS just needs to prove that EGD and FGB are congruent.
2. Prove that △ACD is congruent to △AED [It is not necessary to prove congruence. ..The distance from the points on the bisector of the angle to both sides of the angle is equal~]
Obtain CD=DE AC= AE
AB=AE+EB=8
So AB=CB+EB=8
CB=CD+DB
So AB=ED+BD+BE
Perimeter~We will see it later~ ~
3.∠1+∠AEH+∠AHE=180
∠2+∠BHD+∠ADB=180
Two of them are right angles.. A set of opposite vertex angles
Obtain ∠1=∠2 figure eight`
Prove that AEH is congruent to BEC..
Obtain AH=BC
The three lines of an isosceles triangle merge into one..D is the midpoint of BC...
2BD=BC
∴2BD=AH
Whoop~hit It’s over... I’m so tired... I just typed out a rough idea... I’ll sort it out by myself during the process~ Haha~ Come on!