Grade 2 geometry plus 10 (don't laugh at me, I'm only in grade 1).

Proof: connect MD and me.

÷Δt △ m in CBD is the midpoint of BC,

∴MD= 65438+ 0/2 BC,

∵Rt△CBE, m is the midpoint of BC,

Me = 65438+0/2 BC,

∴MD=ME,

∫N is the midpoint of DE,

∴NM⊥DE.