According to the meaning of the question, every four figures are circulated, followed by triangular cards, square cards, rectangular cards and trapezoidal cards;
(1) 9 ÷ 4 = 2 ... 1,
So the ninth picture is the first one in the third cycle, and it is a triangular card.
A: Xiaomei gets the triangular card.
(2) Because every four cycles, the trapezoid ranks fourth in each cycle, so if she wants to get the trapezoid, she has to rank fourth.
So Wang Fang can be ranked as: 4×3=12 (bit).
A: He wants to get a trapezoidal card, and the 12th is appropriate.
(3) 2 ÷ 4 = 5,
So the 2th card is the last card in the 5th cycle, which is a trapezoidal card.
6-4=2, these children can all get cards with the same shape as Xiaoyong.
A: He got cards with the same shape as the children No.1, No.6 and No.2 in front.
(5) Those who got rectangular cards were: No.3, 3+4=7 (No.), 7+4=11 (No.) and 11. Xiao Li is in front, so Xiao Ming may be the 15th or 19th.
A: Xiao Ming may be the 15th or 19th.
(6) 4× 7 = 28 (children).
A: A * * * has 28 children.
So the answer is: (1) Triangle; （2）12； (3) ladder; （4）1、6、2； (5)15 or 19; （6）28．