The probability that the offspring has the same genotype as the parent is 1/8, because the probability of occurrence of Aa, Bb, and Cc is each 1/2. Just multiply them together (the algorithm is the same as that of homozygotes) The probability is the same)
The same phenotype as the parent is to seek dominant genes, that is, all contain capital letters (A, B, C), then there are four types: AABbCc, AaBbCc, AaBBCc, and AaBbCC, AA, BB, The probability of CC is 1/4, so AABbCc=1/4*1/2*1/2=1/16. Similarly, the probability of AaBBCc and AaBbCC is also 1/16, and the probability of AaBbCc is 1/2*1 /2*1/2=1/8, just add it up, 1/16+1/16+1/16+1/8=5/16
You can also find the recessive gene To find the probability, after finding the recessive gene probability, you can get it by subtracting 1 (calculate this yourself)
These two solutions are complementary, let’s use each other,