△ABC is an isosceles right triangle, AB=a,
AC=BC= 2 2 a,
So S △ABC = 1 2 AC? BC= 1 2 × 2 a 2? 2 a 2 = a 2 4,
The area of the mid
△ABC is an isosceles right triangle, AB=a,
AC=BC= 2 2 a,
So S △ABC = 1 2 AC? BC= 1 2 × 2 a 2? 2 a 2 = a 2 4,
The area of the middle square is: a 2,
Then the shaded area is: 4× A24+A2 = 2A2.
So the answer is: 2A2.