Find the acceleration of mm.

Force analysis of M: gravity, ground support force and positive pressure on M. Because M can only accelerate to the right, its force is the horizontal component of N.

Nx=Nsin37=Ma 1

Then the force of M is analyzed: the elastic force N' (= n) M exerted by gravity mg, and the horizontal acceleration is ax.

Nsin 37 = the maximum m acceleration in the vertical direction is ay, so the acceleration of m is:

A2 = √ (AX2+AY2) In the non-inertial system, M is also subjected to a horizontal inertial force F to the left. In the reference system of the inclined plane m, m is balanced in the direction perpendicular to the inclined plane, including:

mgcos37=N+fsin37

f=ma 1

Nsin37 = maximum

Solution: a 1 = 0.48 mg/[m+0.36 m]

Ax = 0.48Mg mg/[m+0.36m]

ay=g-(0.64Mg/[M+0.36m]

Please accept my answer. This question has gone beyond the outline of the college entrance examination.