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Master Ta (oral color \ micro/? : 3 9 9 6, 1 9,4)
Solution: Let the analytic expression of quadratic function be y = ax2+bx+c∶ and the symmetry axis be x=4∴-b/2a=4? That is, the quadratic function with b=-8a has two intersections with the X axis and one intersection with the Y axis. Let the intersection with the X axis be (x 1, 0, (x2, 0), and the intersection of x2 > x 1 with the Y axis be (0, c). X 1+x2 can be obtained from the relationship between roots and coefficients. The base of the triangle formed by x 1*x2=c/a is x2-x1x2-x1= √ (x2+x1) 2-4x1* x2 = √ B2/A2-4c.