The box contains two kinds of socks, A and B. The number of socks in A is three times that in B. Take out seven pairs at a time. The socks in A and four pairs of socks in B were taken away.

Let the number of A be x, the number of B be y, and the number of times a * * * takes socks is n..

therefore

x=7n+25 - 1

y=4n - 2

x=3y - 3

Add 3 and 2 to 1.

Get 12n=7n+25, 5n=25, n=5.

X=60，y=20

***80

Or, like this, put socks on n times.

Then type B has 4N pairs, and if it is three times, type A is 12N pairs.

12N-7N=25。 Then N=5.

* * * Yes 16N=80 pairs.